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Americium-243 Has a Decay Constant Of 9.39×1059.39 \times 10 ^ { - 5 }

Question 87

Multiple Choice

Americium-243 has a decay constant of 9.39×1059.39 \times 10 ^ { - 5 } years 1- 1 . How long will it take for a sample of americium-243 to lose one-third of its nuclei?


A) 2960 s2960 \mathrm {~s}
B) 10.6×103y10.6 \times 10 ^ { 3 } \mathrm { y }
C) 7.84×103y7.84 \times 10 ^ { 3 } \mathrm { y }
D) 4.32×103y4.32 \times 10 ^ { 3 } \mathrm { y }
E) 6.44×103y6.44 \times 10 ^ { 3 } \mathrm { y }

Correct Answer:

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