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If the Work Function of a Metal Surface Is 2.20eV2.20 \mathrm { eV }

Question 70

Multiple Choice

If the work function of a metal surface is 2.20eV2.20 \mathrm { eV } , what frequency of incident light would give a maximum kinetic energy of 0.25eV0.25 \mathrm { eV } to the photoelectrons ejected from this surface? (1eV=1.60×( 1 \mathrm { eV } = 1.60 \times 10<sup>19</sup> J,h=6.626×10<sup>34</sup> Js) \left. 10 <sup>- 19</sup> \mathrm {~J} , h = 6.626 \times 10 <sup>- 34</sup>\mathrm {~J} \cdot \mathrm { s } \right)


A) 1.02×1014 Hz1.02 \times 10 ^ { 14 } \mathrm {~Hz}
B) 2.05×1014 Hz2.05 \times 10 ^ { 14 } \mathrm {~Hz}
C) 5.92×1014 Hz5.92 \times 10 ^ { 14 } \mathrm {~Hz}
D) 2.50×1014 Hz2.50 \times 10 ^ { 14 } \mathrm {~Hz}
E) 3.53×1014 Hz3.53 \times 10 ^ { 14 } \mathrm {~Hz}

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