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The Spacing of the Atoms of a Crystal Is 159pm159 \mathrm { pm }

Question 67

Multiple Choice

The spacing of the atoms of a crystal is 159pm159 \mathrm { pm } . A monoenergetic beam of neutrons directed normally at the surface of the crystal undergoes first order diffraction at an angle of 5858 ^ { \circ } from the normal. What is the energy of each of the neutrons? ( mneutron =1.675×1027 kg,1eV=1.6×m _ { \text {neutron } } = 1.675 \times 10 ^ { - 27 } \mathrm {~kg} , 1 \mathrm { eV } = 1.6 \times 1019 J,h=6.626×1034 Js) \left. 10 ^ { - 19 } \mathrm {~J} , h = 6.626 \times 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s } \right)


A) 0.050eV0.050 \mathrm { eV }
B) 0.039eV0.039 \mathrm { eV }
C) 0.056eV0.056 \mathrm { eV }
D) 0.061eV0.061 \mathrm { eV }
E) 0.045eV0.045 \mathrm { eV }

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