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A Proton Moving with a Velocity Of 4.0×104 m/s4.0 \times 10 ^ { 4 } \mathrm {~m} / \mathrm { s }

Question 70

Multiple Choice

A proton moving with a velocity of 4.0×104 m/s4.0 \times 10 ^ { 4 } \mathrm {~m} / \mathrm { s } enters a magnetic field of 0.20 T0.20 \mathrm {~T} . If the angle between the velocity of the proton and the direction of the magnetic field is 6060 ^ { \circ } , what is the magnitude of the magnetic force on the proton? (e=1.60×1019C) \left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } \right)


A) 0.60×1015 N0.60 \times 10 ^ { - 15 } \mathrm {~N}
B) 2.2×1015 N2.2 \times 10 ^ { - 15 } \mathrm {~N}
C) 1.1×1015 N1.1 \times 10 ^ { - 15 } \mathrm {~N}
D) 3.3×1015 N3.3 \times 10 ^ { - 15 } \mathrm {~N}
E) 1.8×1015 N1.8 \times 10 ^ { - 15 } \mathrm {~N}

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