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The Magnetic Field Due to the Current in a Long 8.0μT8.0 \mu T

Question 73

Multiple Choice

The magnetic field due to the current in a long, straight wire is 8.0μT8.0 \mu T at a distance of 4.0 cm4.0 \mathrm {~cm} from the center of the wire. What is the current in the wire? (μ0=4π×107 Tm/A) \left( \mu _ { 0 } = 4 \pi \times 10 ^ { - 7 } \mathrm {~T} \cdot \mathrm { m } / \mathrm { A } \right)


A) 0.20 A0.20 \mathrm {~A}
B) 3.2 A3.2 \mathrm {~A}
C) 1.6 A1.6 \mathrm {~A}
D) 0.80 A0.80 \mathrm {~A}
E) 0.40 A0.40 \mathrm {~A}

Correct Answer:

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