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Solve the Equation for Exact Solutions (sec⁡α+tan⁡α)2=1+sin⁡α1−sin⁡α( \sec \alpha + \tan \alpha ) ^ { 2 } = \frac { 1 + \sin \alpha } { 1 - \sin \alpha }

Question 58

Essay

Solve the equation for exact solutions.
- (sec⁡α+tan⁡α)2=1+sin⁡α1−sin⁡α( \sec \alpha + \tan \alpha ) ^ { 2 } = \frac { 1 + \sin \alpha } { 1 - \sin \alpha }

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\[\begin{array} { l }
( \sec \alpha + \...

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