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Solve the Problem V=189sin120πt\mathrm { V } = 189 \sin 120 \pi \mathrm { t }

Question 63

Multiple Choice

Solve the problem.
-Suppose that for an electrical appliance, voltage is given by V=189sin120πt\mathrm { V } = 189 \sin 120 \pi \mathrm { t } and amperage by I=1.07sin120πtI = 1.07 \sin 120 \pi t , where tt is time in seconds. Use identities to write the wattage W=VIW = V I in the form W=acosωt+c\mathrm { W } = \mathrm { a } \cos \omega \mathrm { t } + \mathrm { c } .


A) W=101.115cos120πt+101.115W = - 101.115 \cos 120 \pi t + 101.115
B) W=101.115cos240πt+101.115W = - 101.115 \cos 240 \pi t + 101.115
C) W=202.23cos240πt+202.23\mathrm { W } = - 202.23 \cos 240 \pi \mathrm { t } + 202.23
D) W=101.115cos240πt101.115\mathrm { W } = 101.115 \cos 240 \pi t - 101.115

Correct Answer:

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