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Solve the System {x+5y+2z=52y+5z=6z=2\left\{ \begin{array} { r } x + 5 y + 2 z = 5 \\2 y + 5 z = - 6 \\z = - 2\end{array} \right.

Question 46

Multiple Choice

Solve the system. If there is no solution or if the system's equations are dependent, so state.
- {x+5y+2z=52y+5z=6z=2\left\{ \begin{array} { r } x + 5 y + 2 z = 5 \\2 y + 5 z = - 6 \\z = - 2\end{array} \right.


A) infinitely many solutions; dependent equations
B) no solution or \varnothing
C) {(1,2,2) }\{ ( - 1,2 , - 2 ) \}
D) {(1,2,2) }\{ ( - 1 , - 2,2 ) \}

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