Solved

Solve the System {x+y+z=2xy2z=103x+3y+3z=6\left\{ \begin{array} { r r } x + y + z = & 2 \\x - y - 2 z = & - 10 \\3 x + 3 y + 3 z = & 6\end{array} \right.

Question 32

Multiple Choice

Solve the system. If there is no solution or if the system's equations are dependent, so state.
- {x+y+z=2xy2z=103x+3y+3z=6\left\{ \begin{array} { r r } x + y + z = & 2 \\x - y - 2 z = & - 10 \\3 x + 3 y + 3 z = & 6\end{array} \right.


A) infinitely many solutions; dependent equations
B) {(4,4,2) }\{ ( - 4,4,2 ) \}
C) no solution or \varnothing
D) {(4,2,4) }\{ ( - 4,2,4 ) \}

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions