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Solve the Problem 4545 ^ { \circ } To the Horizontal, with a Muzzle Velocity of 380 Feet

Question 155

Multiple Choice

Solve the problem.
-A projectile is fired from a cliff 200 feet above the water at an inclination of 4545 ^ { \circ } to the horizontal, with a muzzle velocity of 380 feet per second. The height h of the projectile above the water is given by h (x) =32x2(380) 2+x+200( x ) = \frac { - 32 x ^ { 2 } } { ( 380 ) ^ { 2 } } + x + 200 , where xx is the horizontal distance of the projectile from the base of the cliff. Find the maximum height of the projectile.


A) 2256.25 ft
B) 3584.38 ft
C) 1128.13 ft
D) 1328.13 ft

Correct Answer:

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