The function f is one-to-one. State the domain and the range of f and f^-1. Write the domain and range in set-builder
notation.
-

f ( x ) = \frac { 1 } { 4 x + 3 }

f ( x ) : D = \left\{ x \mid x \neq \frac { 3 } { 4 } \right\} , R = \{ y \mid y \neq - 3 \}

;

\mathrm { f } ^ { - 1 } ( \mathrm { x } ) : \mathrm { D } = \left\{ \mathrm { x } | \mathrm { x } \neq - 3 \rangle , R = \left\{ \mathrm { y } \mid \mathrm { y } \neq \frac { 3 } { 4 } \right\} \right.

f ( x ) : D = \left\{ x \mid x z - \frac { 3 } { 4 } \right\} , R = \{ y \mid y \neq 0 \}

;

f ^ { - 1 } ( x ) : D = \{ x \mid x \neq 0 \} , R = \left\{ y \mid y \neq - \frac { 3 } { 4 } \right\}

f ( x )

: D is all real numbers,

R

is all real numbers;

\mathrm { f } ^ { - 1 } ( \mathrm { x } )

\mathrm { D }

is all real numbers,

\mathrm { R }

is all real numbers

D)

f ( x ) : D = \left\{ x \mid x \neq \frac { 1 } { 4 } \right\} , R = \left\{ y \mid y \neq \frac { 1 } { 3 } \right\}

\mathrm { f } ^ { - 1 } ( \mathrm { x } ) : \mathrm { D } = \left\{ \mathrm { x } \mid \mathrm { x } \neq \frac { 1 } { 3 } \right\} , R = \left\{ \mathrm { y } \mid \mathrm { y } \neq \frac { 1 } { 4 } \right\}

Graph the Function by Starting with the Graph of the Basic

Multiple Choice