Find the rule that defines each piecewise-defined function.
- $Find the rule that defines each piecewise-defined function. - A) f ( x ) = \left\{ \begin{array} { l l } \frac { 4 } { 3 } x + 4 & \text { if } - 3 \leq x \leq 0 \\ \frac { 2 } { 3 } x & \text { if } 0 < x \leq 3 \end{array} \right. B) f ( x ) = \left\{ \begin{array} { l l } \frac { 3 } { 4 } x + 4 & \text { if } - 3 \leq x \leq 0 \\ \frac { 3 } { 2 } x & \text { if } x > 0 \end{array} \right. C) f ( x ) = \left\{ \begin{array} { l l } \frac { 3 } { 4 } x + 4 & \text { if } - 3 \leq x \leq 0 \\ \frac { 3 } { 2 } x & \text { if } x \geq 0 \end{array} \right. D) f ( x ) = \left\{ \begin{array} { l l } \frac { 4 } { 3 } x + 4 & \text { if } - 3 \leq x \leq 0 \\ \frac { 2 } { 3 } x & \text { if } x > 0 \end{array} \right.$

A)

f ( x ) = \left\{ \begin{array} { l l } \frac { 4 } { 3 } x + 4 & \text { if } - 3 \leq x \leq 0 \\ \frac { 2 } { 3 } x & \text { if } 0 < x \leq 3 \end{array} \right.

f ( x ) = \left\{ \begin{array} { l l } \frac { 3 } { 4 } x + 4 & \text { if } - 3 \leq x \leq 0 \\ \frac { 3 } { 2 } x & \text { if } x > 0 \end{array} \right.

f ( x ) = \left\{ \begin{array} { l l } \frac { 3 } { 4 } x + 4 & \text { if } - 3 \leq x \leq 0 \\ \frac { 3 } { 2 } x & \text { if } x \geq 0 \end{array} \right.

f ( x ) = \left\{ \begin{array} { l l } \frac { 4 } { 3 } x + 4 & \text { if } - 3 \leq x \leq 0 \\ \frac { 2 } { 3 } x & \text { if } x > 0 \end{array} \right.

For the Given Functions F and G, Find the Requested f(x)=x+7,g(x)=8x−11;f ( x ) = \sqrt { x + 7 } , g ( x ) = 8 x - 11 ; \quadf(x)=x+7​,g(x)=8x−11;

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For the Given Functions F and G, Find the Requested $f ( x ) = \sqrt { x + 7 } , g ( x ) = 8 x - 11 ; \quad$

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