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Find the Standard Form of the Equation of the Ellipse 8x2+4y2+64x32y+32=08 x ^ { 2 } + 4 y ^ { 2 } + 64 x - 32 y + 32 = 0

Question 85

Multiple Choice

Find the standard form of the equation of the ellipse below.
8x2+4y2+64x32y+32=08 x ^ { 2 } + 4 y ^ { 2 } + 64 x - 32 y + 32 = 0


A) (x4) 2(25) 2+(y+4) 2(210) 2=1\frac { ( x - 4 ) ^ { 2 } } { ( 2 \sqrt { 5 } ) ^ { 2 } } + \frac { ( y + 4 ) ^ { 2 } } { ( 2 \sqrt { 10 } ) ^ { 2 } } = 1
B) (x+4) 2(25) 2+(y4) 2(210) 2=1\frac { ( x + 4 ) ^ { 2 } } { ( 2 \sqrt { 5 } ) ^ { 2 } } + \frac { ( y - 4 ) ^ { 2 } } { ( 2 \sqrt { 10 } ) ^ { 2 } } = 1
C) (x+4) 2(210) 2(y4) 2(25) 2=1\frac { ( x + 4 ) ^ { 2 } } { ( 2 \sqrt { 10 } ) ^ { 2 } } - \frac { ( y - 4 ) ^ { 2 } } { ( 2 \sqrt { 5 } ) ^ { 2 } } = 1
D) (x4) 2(210) 2+(y+4) 2(25) 2=1\frac { ( x - 4 ) ^ { 2 } } { ( 2 \sqrt { 10 } ) ^ { 2 } } + \frac { ( y + 4 ) ^ { 2 } } { ( 2 \sqrt { 5 } ) ^ { 2 } } = 1
E) (x4) 2(25) 2(y+4) 2(210) 2=1\frac { ( x - 4 ) ^ { 2 } } { ( 2 \sqrt { 5 } ) ^ { 2 } } - \frac { ( y + 4 ) ^ { 2 } } { ( 2 \sqrt { 10 } ) ^ { 2 } } = 1

Correct Answer:

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