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Use the Quadratic Formula to Solve For yy In the Following Equation

Question 88

Multiple Choice

Use the Quadratic Formula to solve for yy in the following equation.
49x242xy+9y290x10y=049 x ^ { 2 } - 42 x y + 9 y ^ { 2 } - 90 x - 10 y = 0


A) 21x5±42x+8359\frac { - 21 x - 5 \pm \sqrt { - 42 x + 835 } } { 9 }
B) 2(21x+5) ±42x+33409\frac { 2 ( 21 x + 5 ) \pm \sqrt { - 42 x + 3340 } } { 9 }
C) 21x+5±1020x+259\frac { 21 x + 5 \pm \sqrt { 1020 x + 25 } } { 9 }
D) 42x+10±21x+164518\frac { 42 x + 10 \pm \sqrt { - 21 x + 1645 } } { 18 }
E) 42x10±21x+91018\frac { - 42 x - 10 \pm \sqrt { - 21 x + 910 } } { 18 }

Correct Answer:

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