Solve the Initial Value Problem $$\theta ^ { 2 } \frac { d y } { d \theta } - 3 \theta y = \theta ^ { 5 } \sec \theta \tan \theta ; \theta > 0 , y ( \pi ) = 0$$

Multiple Choice

Solve the initial value problem.
- $$\theta ^ { 2 } \frac { d y } { d \theta } - 3 \theta y = \theta ^ { 5 } \sec \theta \tan \theta ; \theta > 0 , y ( \pi ) = 0$$

A) $y = - \frac { \theta ^ { 2 } } { \cos \theta } - \theta ^ { 2 } , \theta > 0$
B) $y = \frac { \theta ^ { 3 } } { \cos \theta } + \theta ^ { 3 } , \theta > 0$
C) $y = \frac { \theta ^ { 2 } } { \cos \theta } + \theta ^ { 2 } , \theta > 0$
D) $y = - \frac { \theta ^ { 3 } } { \cos \theta } - \theta ^ { 3 } , \theta > 0$