Solve
-A Local Pond Can Only Hold Up to 53 $\frac { \mathrm { dP } } { \mathrm { dt } } = ( 0.0015 ) ( 53 - \mathrm { P } ) \mathrm { P }$

Multiple Choice

Solve.
-A local pond can only hold up to 53 geese. Seven geese are introduced into the pond. Assume that the rate of grow th of the population is $\frac { \mathrm { dP } } { \mathrm { dt } } = ( 0.0015 ) ( 53 - \mathrm { P } ) \mathrm { P }$ where $t$ is time in weeks. How long will it take for the goose population to be 25 ?

A) 22.26 weeks
B) 46.73 weeks
C) 26.02 weeks
D) 14.23 weeks