Solve the Initial Value Problem for Y as a Function $$\left( 36 - x ^ { 2 } \right) \frac { d y } { d x } = 1 , y ( 0 ) = 3$$

Multiple Choice

Solve the initial value problem for y as a function of x.
- $$\left( 36 - x ^ { 2 } \right) \frac { d y } { d x } = 1 , y ( 0 ) = 3$$

A) $y = \frac { 1 } { 6 } \ln | \sec x + \tan x | + 3$
B) $y = \frac { x } { 36 \sqrt { 36 - x ^ { 2 } } } + 3$
C) $y = \frac { 1 } { 12 } \ln \left| \frac { x + 6 } { x - 6 } \right| + 3$
D) $y = \frac { 1 } { 12 } \ln \left| \frac { x + 6 } { x - 6 } \right|$