Find the Absolute Extreme Values of the Function on the Interval

Multiple Choice

Find the absolute extreme values of the function on the interval.
- $$f ( x ) = \ln ( x + 2 ) + \frac { 1 } { x } , 1 \leq x \leq 6$$

A) Minimum value is $- 1$ at $x = - 1$ ; maximum value is $\ln 8 + \frac { 1 } { 6 }$ at $x = 6$
B) Minimum value is $\ln 3 + 1$ at $x = 1$ ; maximum value is $\ln 8 + \frac { 1 } { 6 }$ at $x = 6$
C) Minimum value is $\ln 4 + \frac { 1 } { 2 }$ at $x = 2$ ; maximum value is $\ln 3 + 1$ at $x = 1$
D) Minimum value is $\ln 4 + \frac { 1 } { 2 }$ at $x = 2$ ; maximum value is $\ln 8 + \frac { 1 } { 6 }$ at $x = 6$