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Find the Extreme Values of the Function and Where They y=1x2+1y = \frac { 1 } { x ^ { 2 } + 1 }

Question 255

Multiple Choice

Find the extreme values of the function and where they occur.
- y=1x2+1y = \frac { 1 } { x ^ { 2 } + 1 }


A) The maximum value is 1 at x = 0.5, the minimum value is -1 at x = 0.5.
B) The minimum value is -1 at x = 0.5.
C) The maximum value is 1 at x = 0.5.
D) The maximum value is 1 at x = 0.

Correct Answer:

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