Find the Derivative at Each Critical Point and Determine the Local

Multiple Choice

Find the derivative at each critical point and determine the local extreme values.
- $y=x^{2} \sqrt{9-x}$

A)
$\begin{array}{l|l|l|l}\text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\\hline x=0 & 0 & \text { min } & 0 \\x=9 & \text { undefined } & \text { min } & 0 \\x=\frac{36}{5} & 0 & \text { local max } & \frac{3888}{125} \sqrt{5}\end{array}$

B)
$\begin{array}{l|l|l|l}\text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\\hline x=9 & \text { undefined } & \text { min } & 0 \\x=\frac{36}{5} & 0 & \text { local max } & \frac{3888}{125} \sqrt{5}\end{array}$

C)
$\begin{array}{l|l|l|l}\text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\\hline x=0 & 0 & \min & 0 \\x=9 & 0 & \min & 0 \\x=\frac{36}{5} & 0 & \text { local max } & \frac{3888}{125} \sqrt{5}\end{array}$

D)
$\begin{array}{l|l|l|l}\text { Critical Pt.| } & \text { derivative } & \text { Extremum } & \text { Value } \\\hline \mathrm{x}=\frac{36}{5} & 0 & \text { local max } & \frac{3888}{125} \sqrt{5}\end{array}$