Solve the Initial Value Problem $$\frac { d y } { d x } = \frac { 1 } { x + 5 } , y ( - 4 ) = 6$$

Multiple Choice

Solve the initial value problem.
- $$\frac { d y } { d x } = \frac { 1 } { x + 5 } , y ( - 4 ) = 6$$

A) $y = \ln ( x + 5 ) + 6$
B) $y = - \frac { 1 } { ( x + 5 ) ^ { 2 } } + 6$
C) $y = - \frac { 1 } { ( x + 5 ) ^ { 2 } } + 7$
D) $y = \ln ( x + 5 ) + 6 - \ln 2$