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Solve the Problem 36ft/sec36 \mathrm { ft } / \mathrm { sec }

Question 416

Multiple Choice

Solve the problem.
-The driver of a car traveling at 36ft/sec36 \mathrm { ft } / \mathrm { sec } suddenly applies the brakes. The position of the car is s=36t3t2s = 36 \mathrm { t } - 3 \mathrm { t } ^ { 2 } , tt seconds after the driver applies the brakes. How far does the car go before coming to a stop?


A) 432 ft
B) 108 ft
C) 216 ft
D) 6 ft

Correct Answer:

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