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Find the Derivative y=10sinx+1cotxy = \frac { 10 } { \sin x } + \frac { 1 } { \cot x }

Question 270

Multiple Choice

Find the derivative.
- y=10sinx+1cotxy = \frac { 10 } { \sin x } + \frac { 1 } { \cot x }


A) y=10cscxcotxcsc2xy ^ { \prime } = 10 \csc x \cot x - \csc ^ { 2 } x
B) y=10cscxcotxsec2xy ^ { \prime } = 10 \csc x \cot x - \sec ^ { 2 } x
C) y=10cosxcsc2xy ^ { \prime } = 10 \cos x - \csc ^ { 2 } x
D) y=10cscxcotx+sec2xy ^ { \prime } = - 10 \csc x \cot x + \sec ^ { 2 } x

Correct Answer:

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