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Solve the Problem v=ks(k\mathrm { v } = \frac { \mathrm { k } } { \mathrm { s } } ( \mathrm { k }

Question 325

Multiple Choice

Solve the problem.
-Suppose that the velocity of a falling body is v=ks(k\mathrm { v } = \frac { \mathrm { k } } { \mathrm { s } } ( \mathrm { k } a constant) at the instant the body has fallen s meters from its starting point. Find the body's acceleration as a function of s.


A) a=k2s3a = - \frac { k ^ { 2 } } { s ^ { 3 } }
B) a=1s2a = - \frac { 1 } { s ^ { 2 } }
C) a=k2s3a = \frac { k ^ { 2 } } { s ^ { 3 } }
D) a=ks2a = - \frac { k } { s ^ { 2 } }

Correct Answer:

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