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 Find the limit using limx=0sinxx=1\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }

Question 267

Multiple Choice

 Find the limit using limx=0sinxx=1\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }
- limx06x2(cot3x) (csc2x) \lim _ { x \rightarrow 0 } 6 x ^ { 2 } ( \cot 3 x ) ( \csc 2 x )


A) does not exist
B) 13\frac { 1 } { 3 }
C) 12\frac { 1 } { 2 }
D) 1

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