Provide an Appropriate Response $\varepsilon > 0$ , Find an Interval $\mathrm { I } = ( 3 - \delta , 3 ) , \delta > 0$

Multiple Choice

Provide an appropriate response.
-Given $\varepsilon > 0$ , find an interval $\mathrm { I } = ( 3 - \delta , 3 ) , \delta > 0$ , such that if $x$ lies in $\mathrm { I }$ , then $\sqrt { 3 - x } < \varepsilon$ . What limit is being verified and what is its value?

A) $\lim _ { x \rightarrow 8 ^ { - } } \sqrt { 3 - x } = 0$
B) $\lim _ { x \rightarrow 8 ^ { - } } \sqrt { x } = 3$
C) $\lim _ { x \rightarrow 8 ^ { + } } \sqrt { 3 - x } = 0$
D) $\lim _ { x \rightarrow \theta ^ { - } } \sqrt { 3 - x } = 0$