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Calculate the Flux of the Field F Across the Closed F=y2i+x3j\mathbf { F } = \mathrm { y } ^ { 2 } \mathbf { i } + \mathrm { x } ^ { 3 } \mathbf { j }

Question 14

Multiple Choice

Calculate the flux of the field F across the closed plane curve C.
- F=y2i+x3j\mathbf { F } = \mathrm { y } ^ { 2 } \mathbf { i } + \mathrm { x } ^ { 3 } \mathbf { j } ; the curve C\mathrm { C } is the closed counterclockwise path formed from the semicircle r(t) =3costi+3\mathbf { r } ( \mathrm { t } ) = 3 \cos \mathrm { ti } + 3 sin j\mathrm { j } , 0tπ0 \leq t \leq \pi , and the straight line segment from (3,0) ( - 3,0 ) to (3,0) ( 3,0 )


A) =272= \frac { 27 } { 2 }
B) 0
C) 272\frac { 27 } { 2 }
D) 27

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