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Calculate the Flux of the Field F Across the Closed F=e5xi+e2yj\mathbf { F } = \mathrm { e } ^ { 5 \mathrm { x } _ { \mathrm { i } } + \mathrm { e } ^ { 2 } \mathrm { y } } \mathrm { j }

Question 19

Multiple Choice

Calculate the flux of the field F across the closed plane curve C.
- F=e5xi+e2yj\mathbf { F } = \mathrm { e } ^ { 5 \mathrm { x } _ { \mathrm { i } } + \mathrm { e } ^ { 2 } \mathrm { y } } \mathrm { j } ; the curve C\mathrm { C } is the closed counterclockwise path around the triangle with vertices at (0,0) ,(5,0) ( 0,0 ) , ( 5,0 ) , and (0,1) ( 0,1 )


A) 15e25(1e5) +52(e21) +6\frac { 1 } { 5 } e ^ { 25 } \left( 1 - e ^ { - 5 } \right) + \frac { 5 } { 2 } \left( e ^ { 2 } - 1 \right) + 6
B) 125e25(1e25) +52(e21) 6\frac { 1 } { 25 } \mathrm { e } ^ { 25 } \left( 1 - \mathrm { e } ^ { - 25 } \right) + \frac { 5 } { 2 } \left( \mathrm { e } ^ { 2 } - 1 \right) - 6
C) 15e25(e51) +52(1e2) 6\frac { 1 } { 5 } \mathrm { e } ^ { 25 } \left( \mathrm { e } ^ { - 5 } - 1 \right) + \frac { 5 } { 2 } \left( 1 - \mathrm { e } ^ { 2 } \right) - 6
D) 0

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