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Calculate the Flow in the Field F Along the Path F=e2i+1yj+2k,C\mathbf { F } = \mathrm { e } ^ { 2 } \mathrm { i } + \frac { 1 } { \mathrm { y } } \mathrm { j } + 2 \mathbf { k } , \mathrm { C }

Question 74

Multiple Choice

Calculate the flow in the field F along the path C.
- F=e2i+1yj+2k,C\mathbf { F } = \mathrm { e } ^ { 2 } \mathrm { i } + \frac { 1 } { \mathrm { y } } \mathrm { j } + 2 \mathbf { k } , \mathrm { C } is the curve r(t) =4t2i+5tj+(82t) k,1t3\mathbf { r } ( \mathrm { t } ) = 4 \mathrm { t } ^ { 2 } \mathrm { i } + 5 \mathrm { tj } + ( - 8 - 2 \mathrm { t } ) \mathbf { k } , 1 \leq \mathrm { t } \leq 3


A) 4(e225e25) +ln384 \left( \mathrm { e } ^ { 225 } - \mathrm { e } ^ { 25 } \right) + \ln 3 - 8
B) 825(e225e25) +ln38\frac { 8 } { 25 } \left( \mathrm { e } ^ { 225 } - \mathrm { e } ^ { 25 } \right) + \ln 3 - 8
C) 425(e225e25) +ln38\frac { 4 } { 25 } \left( e ^ { 225 } - e ^ { 25 } \right) + \ln 3 - 8
D) 425(e225e25) +ln3+8\frac { 4 } { 25 } \left( \mathrm { e } ^ { 225 } - \mathrm { e } ^ { 25 } \right) + \ln 3 + 8

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