Find the Equation for the Plane Tangent to the Parametrized

Short Answer

Find the equation for the plane tangent to the parametrized surface S at the point P.
- $$S \text { is the cylinder } r ( \theta , z ) = 6 \cos ^ { 2 } \theta \mathbf { i } + 3 \sin 2 \theta \mathbf { j } + \mathrm { zk } ; \mathrm { P } \text { is the point corresponding to } ( \theta , z ) = \left( \frac { \pi } { 4 } , - 1 \right)$$