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    Mathematics
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    Thomas Calculus Early Transcendentals
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    Exam 15: Partial Derivatives
  5. Question
    Find Two Paths of Approach from Which One Can Conclude\[f ( x , y ) = \frac { y ^ { 2 } } { y ^ { 2 } - x }\]
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Find Two Paths of Approach from Which One Can Conclude f(x,y)=y2y2−xf ( x , y ) = \frac { y ^ { 2 } } { y ^ { 2 } - x }f(x,y)=y2−xy2​

Question 345

Question 345

Essay

Find two paths of approach from which one can conclude that the function has no limit as (x, y) approaches (0, 0).
- f(x,y)=y2y2−xf ( x , y ) = \frac { y ^ { 2 } } { y ^ { 2 } - x }f(x,y)=y2−xy2​

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