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Find an Equation for the Line Tangent to the Curve x=10t27,y=t3,t=1x = 10 t ^ { 2 } - 7 , y = t ^ { 3 } , t = 1

Question 143

Multiple Choice

Find an equation for the line tangent to the curve at the point defined by the given value of t.
- x=10t27,y=t3,t=1x = 10 t ^ { 2 } - 7 , y = t ^ { 3 } , t = 1


A) y=320x1120y = \frac { 3 } { 20 } x - \frac { 11 } { 20 }
B) y=310x+1y = \frac { 3 } { 10 } x + 1
C) y=203x1120y = \frac { 20 } { 3 } x - \frac { 11 } { 20 }
D) y=320x+1120y = \frac { 3 } { 20 } x + \frac { 11 } { 20 }

Correct Answer:

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