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Solve the Problem f(x)=x2f ( x ) = \sqrt { x - 2 }

Question 183

Multiple Choice

Solve the problem.
-Let f(x) =x2f ( x ) = \sqrt { x - 2 } . Find a function y=g(x) y = g ( x ) so that (fg) (x) =x22( f \circ g ) ( x ) = \sqrt { x ^ { 2 } - 2 } .


A) g(x) =x2+2g ( x ) = x ^ { 2 } + 2
B) g(x) =2xg ( x ) = 2 x
C) g(x) =x2g ( x ) = x ^ { 2 }
D) g(x) =x22g ( x ) = x ^ { 2 } - 2

Correct Answer:

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