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Use the Center, Vertices, and Asymptotes to Graph the Hyperbola $\frac { ( y + 2 ) ^ { 2 } } { 9 } - \frac { ( x - 2 ) ^ { 2 } } { 4 } = 1$

Question 80

Multiple Choice

Use the center, vertices, and asymptotes to graph the hyperbola.
- $\frac { ( y + 2 ) ^ { 2 } } { 9 } - \frac { ( x - 2 ) ^ { 2 } } { 4 } = 1$
$Use the center, vertices, and asymptotes to graph the hyperbola. - \frac { ( y + 2 ) ^ { 2 } } { 9 } - \frac { ( x - 2 ) ^ { 2 } } { 4 } = 1 A) B) C) D)$

A)
$Use the center, vertices, and asymptotes to graph the hyperbola. - \frac { ( y + 2 ) ^ { 2 } } { 9 } - \frac { ( x - 2 ) ^ { 2 } } { 4 } = 1 A) B) C) D)$
B)
$Use the center, vertices, and asymptotes to graph the hyperbola. - \frac { ( y + 2 ) ^ { 2 } } { 9 } - \frac { ( x - 2 ) ^ { 2 } } { 4 } = 1 A) B) C) D)$
C)
$Use the center, vertices, and asymptotes to graph the hyperbola. - \frac { ( y + 2 ) ^ { 2 } } { 9 } - \frac { ( x - 2 ) ^ { 2 } } { 4 } = 1 A) B) C) D)$
D)
$Use the center, vertices, and asymptotes to graph the hyperbola. - \frac { ( y + 2 ) ^ { 2 } } { 9 } - \frac { ( x - 2 ) ^ { 2 } } { 4 } = 1 A) B) C) D)$

Use the Center, Vertices, and Asymptotes to Graph the Hyperbola (y+2)29−(x−2)24=1\frac { ( y + 2 ) ^ { 2 } } { 9 } - \frac { ( x - 2 ) ^ { 2 } } { 4 } = 19(y+2)2​−4(x−2)2​=1

Multiple Choice

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Use the Center, Vertices, and Asymptotes to Graph the Hyperbola $\frac { ( y + 2 ) ^ { 2 } } { 9 } - \frac { ( x - 2 ) ^ { 2 } } { 4 } = 1$

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