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Solve the Problem 60x+60y30012x+6y3610x+30y90x0y0\begin{array}{l}60 x+60 y \geq 300 \\12 x+6 y \geq 36 \\10 x+30 y \geq 90 \\x \geq 0 \\y \geq 0\end{array}

Question 205

Multiple Choice

Solve the problem.
-The liquid portion of a diet is to provide at least 300 calories, 36 units of vitamin A, and 90 units of vitamin C daily. A cup of dietary drink X provides 60 calories, 12 units of vitamin A, and 10 units of vitamin C. A
Cup of dietary drink Y provides 60 calories, 6 units of vitamin A, and 30 units of vitamin C. Set up a system
Of linear inequalities that describes the minimum daily requirements for calories and vitamins. Let x =
Number of cups of dietary drink X, and y = number of cups of dietary drink Y. Write all the constraints as
A system of linear inequalities.


A) 60x+60y30012x+6y3610x+30y90x0y0\begin{array}{l}60 x+60 y \geq 300 \\12 x+6 y \geq 36 \\10 x+30 y \geq 90 \\x \geq 0 \\y \geq 0\end{array}

B) 60x+60y>30012x+6y>3610x+30y>90x>0y>0 \begin{array}{l}60 x+60 y>300 \\12 x+6 y>36 \\10 x+30 y>90 \\x>0 \\y>0\end{array}

C) 60x+60y30012x+6y>3610x+30y90\begin{array}{l}60 x+60 y \geq 300 \\12 x+6 y>36 \\10 x+30 y \geq 90\end{array}

D) 60x+60y30012x+6y3610x+30y90x0y0\begin{array}{l}60 x+60 y \leq 300 \\12 x+6 y \leq 36 \\10 x+30 y \leq 90 \\x \geq 0 \\y \geq 0\end{array}

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