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Factor Completely 1000p311000 p ^ { 3 } - 1 A) (10p1)(100p2+1)( 10 p - 1 ) \left( 100 p ^ { 2 } + 1 \right)

Question 84

Multiple Choice

Factor completely. If the polynomial cannot be factored, write ʺprime.ʺ
- 1000p311000 p ^ { 3 } - 1


A) (10p1) (100p2+1) ( 10 p - 1 ) \left( 100 p ^ { 2 } + 1 \right)
B) (10p+1) (100p210p+1) ( 10 p + 1 ) \left( 100 p ^ { 2 } - 10 p + 1 \right)
C) (1000p1) (p2+10p+1) ( 1000 p - 1 ) \left( p ^ { 2 } + 10 p + 1 \right)
D) (10p1) (100p2+10p+1) ( 10 p - 1 ) \left( 100 p ^ { 2 } + 10 p + 1 \right)

Correct Answer:

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