The Iodine "Clock Reaction" Involves the Following Sequence of Reactions

Multiple Choice

The iodine "clock reaction" involves the following sequence of reactions occurring in a reaction mixture in a single beaker. 1.IO₃(aq) + 5I⁻(aq) + 6H⁺(aq) → 3I₂(aq) + 3H₂O(l)
2.I₂(aq) + 2S₂O₃²⁻(aq) → 2I⁻(aq) + S₄O₆²⁻aq)
The molecular iodine (I₂) formed in reaction 1 is immediately used up in reaction 2, so that no iodine accumulates. What is the overall reaction occurring in this experiment?

A) IO ₃ ⁻( aq) + 3I ⁻( aq) + 2S ₂O3 ₂ ⁻ aq) + 6H+( aq) → 2I ₂( aq) + S ₄O6 ₂ ⁻( aq) + 3H ₂O( l)
B) IO ₃( aq) + 4S ₂O3 ₂ ⁻( aq) + 6H+( aq) → I ⁻( aq) + 2S ₄O6 ₂ ⁻( aq) + 3H ₂O( l)
C) IO ₃⁻ aq) + 6S ₂O3 ₂ ⁻ aq) + 6H+( aq) → I ^-( aq) + 3S ₄O6 ₂ ⁻ aq) + 3H ₂O( l)
D) IO3 ⁻( aq) + I2( aq) + 8S2O32 ⁻( aq) + 6H+( aq) → 3I-( aq) + 4S4O62 ⁻( aq) + 3H2O( l)
E) IO3( aq) + 2I2( aq) + 6S2O32 ⁻(aq) + 6H+( aq) → 5I ^-( aq) + 3S4O62−( aq) + 3H2O( l)