Mean Free Path: Assuming the Radius of Diatomic Molecules Is

Multiple Choice

Mean free path: Assuming the radius of diatomic molecules is approximately for what pressure will the mean free path in room-temperature (20°C) nitrogen be 4.6 m? The Boltzmann constant is 1.38 × 10^-23 J/K, Avogadro's number is 6.02 × 10²³ molecules/mole, and the ideal gas constant is R = 8.314 J/mol ∙ K = 0.0821 L ∙ atm/mol ∙ K.

A) 4.9 × 10^-8 _atm
B) 6.9 × 10^-8 _atm
C) 1.5 × 10^-7 _atm
D) 2.2 × 10^-7 _atm