For the Same Bivariate Table, Cramer's V Is

Multiple Choice

For the same bivariate table, Cramer's V is .27 and lambda is zero. What can we conclude?

A) a computational mistake has been made. V can never be greater than lambda
B) this is a negative relationship
C) there is no association, disregard V
D) the variables may be associated even if lambda is zero. Disregard lambda if the row marginals are very unequal