A Uniform Rod of Mass M = 1 $\theta$ = 40 $\degree$

Multiple Choice

A uniform rod of mass M = 1.2 kg and length L = 0.80 m, lying on a frictionless horizontal plane, is free to pivot about a vertical axis through one end, as shown. The moment of inertia of the rod about this axis is given by (1/3) ML2. If a force (F = 5.0 N, $\theta$ = 40 $\degree$ ) acts as shown, what is the resulting angular acceleration about the pivot point?

A) 16 rad/s2
B) 12 rad/s2
C) 14 rad/s2
D) 10 rad/s2
E) 33 rad/s2