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Find the Derivative of the Function y=35sec2xy = \frac { 3 } { 5 } \sec ^ { 2 } x

Question 116

Multiple Choice

Find the derivative of the function. y=35sec2xy = \frac { 3 } { 5 } \sec ^ { 2 } x


A) yt=65sec2xtanxy ^ { t } = - \frac { 6 } { 5 } \sec ^ { 2 } x \tan x
B) yt=65sec2xtan2xy ^ { t } = \frac { 6 } { 5 } \sec ^ { 2 } x \tan ^ { 2 } x
C) yt=65secxtanxy ^ {t } = \frac { 6 } { 5 } \sec x \tan x
D) yt=65sec2xtanxy ^ { t } = \frac { 6 } { 5 } \sec ^ { 2 } x \tan x
E) yt=35sec2xtanxy ^ { t } = \frac { 3 } { 5 } \sec ^ { 2 } x \tan x

Correct Answer:

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