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Find an Equation of the Tangent Line to the Graph 7x22xy+4y236=0,(2,1)7 x ^ { 2 } - 2 x y + 4 y ^ { 2 } - 36 = 0 , \quad ( 2 , - 1 )

Question 182

Multiple Choice

Find an equation of the tangent line to the graph of the function given below at the given point. 7x22xy+4y236=0,(2,1) 7 x ^ { 2 } - 2 x y + 4 y ^ { 2 } - 36 = 0 , \quad ( 2 , - 1 ) (The coefficients below are given to two decimal places.)


A) y=7.50x+16.00y = 7.50 x + 16.00
B) y=2.50x+16.00y = 2.50 x + 16.00
C) y=2.50x6.00y = 2.50 x - 6.00
D) y=2.50x6.00y = - 2.50 x - 6.00
E) y=7.50x16.00y = 7.50 x - 16.00

Correct Answer:

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