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The Height of an Object T Seconds After It Is s(t)=4.9t2+250s ( t ) = - 4.9 t ^ { 2 } + 250

Question 129

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The height of an object t seconds after it is dropped from a height of 250 meters is s(t) =4.9t2+250s ( t ) = - 4.9 t ^ { 2 } + 250 . Find the time during the first 8 seconds of fall at which the instantaneous velocity equals the average velocity.


A) 32 seconds
B) 19.619.6 seconds
C) 6.386.38 seconds
D) 4 seconds
E) 2.452.45 seconds

Correct Answer:

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