$t = \frac { 10 } { \ln 2 } \int _ { 250 } ^ { 340 } \frac { 1 } { T - 70 } d T$

Multiple Choice

$\text { Find the time required for an object to cool from } 340 ^ { \circ } \mathrm { F } \text { to } 250 ^ { \circ } \mathrm { F } \text { by evaluating }$ $t = \frac { 10 } { \ln 2 } \int _ { 250 } ^ { 340 } \frac { 1 } { T - 70 } d T$ , where $t$ is time in minutes. Round your answer to four decimal places.

A) $6.4346$ minutes
B) $4.4251$ minutes
C) $3.6907$ minutes
D) $4.0598$ minutes
E) $5.8496$ minutes