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Solve the Differential Equation yt=2xyy ^ { t } = \frac { - 2 x } { y }

Question 73

Multiple Choice

Solve the differential equation. yt=2xyy ^ { t } = \frac { - 2 x } { y }


A) y2=2x2+Cy ^ { 2 } = 2 x ^ { 2 } + C
B) 2lny=2x2+C2 \ln y = - 2 x ^ { 2 } + C
C) 2lny=2x3+C2 \ln y = 2 x ^ { 3 } + C
D) y2=2x2+Cy ^ { 2 } = - 2 x ^ { 2 } + C
E) y2=2x3+Cy ^ { 2 } = - 2 x ^ { 3 } + C

Correct Answer:

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