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Find the Area of the Inner Loop Of r=3+6sinθr = 3 + 6 \sin \theta

Question 7

Multiple Choice

Find the area of the inner loop of r=3+6sinθr = 3 + 6 \sin \theta


A)
27π+272227 \pi + \frac { 27 \sqrt { 2 } } { 2 }
B)
9π27349 \pi - \frac { 27 \sqrt { 3 } } { 4 }
C)
27π273427 \pi - \frac { 27 \sqrt { 3 } } { 4 }
D)
9π27329 \pi - \frac { 27 \sqrt { 3 } } { 2 }
E)
9π+27229 \pi + \frac { 27 \sqrt { 2 } } { 2 }

Correct Answer:

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