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Suppose the Formula for Wind Chill C (In Degrees Fahrenheit) C=37.05+0.6844T37.59v0.16+0.4425Tv0.16C = 37.05 + 0.6844 T - 37.59 v ^ { 0.16 } + 0.4425 T v ^ { 0.16 }

Question 20

Multiple Choice

Suppose the formula for wind chill C (in degrees Fahrenheit) is given by C=37.05+0.6844T37.59v0.16+0.4425Tv0.16C = 37.05 + 0.6844 T - 37.59 v ^ { 0.16 } + 0.4425 T v ^ { 0.16 } where vv is the wind speed in miles per hour and TT is the temperature in degrees Fahrenheit. The wind speed is 23±323 \pm 3 miles per hour and the temperature is 8±18 ^ { \circ } \pm 1 ^ { \circ } Fahrenheit. Use dCd C to estimate the relative error in calculating the wind chill. Round your answer to two decimal places.


A) dCC=±12.62\frac { d C } { C } = \pm 12.62
B) dCC=±17.81\frac { d C } { C } = \pm 17.81
C) dC+C=±12.81\frac { d C ^ { + } } { C } = \pm 12.81
D) dCCc=±12.62\frac { d C } { C ^ { c } } = \pm 12.62
E) dCC=±0.19\frac { d C } { C } = \pm 0.19

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