Find the Derivative at Each Critical Point and Determine the Local

Multiple Choice

Find the derivative at each critical point and determine the local extreme values.
- $y = x \left( 4 - x ^ { 2 } \right)$

A)
$\begin{array}{l|l|l|r}\text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\\hline x=-1.15 & 0 & \text { local max } & 3.08 \\x=1.15 & 0 & \text { local min } & -6.16\end{array}$

B)
$\begin{array}{l|l|l|r}\text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\\hline x=1.15 & 0 & \text { local max } & 3.08 \\x=-1.15 & 0 & \text { local min } & -3.08\end{array}$

C)
$\begin{array}{c|l|l|c}\text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\\hline x=-1.15 & 0 & \text { local max } & -6.16 \\x=1.15 & 0 & \text { local min } & 3.08\end{array}$

D)
$\begin{array}{l|l|l|r}\text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\\hline \mathrm{x}=1.15 & 0 & \text { local max } & -6.16 \\\mathrm{x}=-1.15 & 0 & \text { local min } & 3.08\end{array}$