Find the Derivative at Each Critical Point and Determine the Local

Multiple Choice

Find the derivative at each critical point and determine the local extreme values.
- $$y = \left\{ \begin{array} { l } 6 - 2 x , x \leq 1 \\x + 3 , x > 1\end{array} \right.$$

A)
$\begin{array}{l|l|l|l}\text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\\hline x=1 & \text { undefined } & \text { minimum } & 4\end{array}$

B)
$\begin{array}{l|l|l|l}\text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\\hline x=2 & \text { undefined } & \text { minimum } & 5\end{array}$

C)
$\begin{array}{l|l|l|l}\text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\\hline x=1 & 0 & \text { minimum } & 4\end{array}$

D)
$\begin{array}{l|l|l|l}\text { Critical Pt. } & \text { derivative } & \text { Extremum } & \text { Value } \\\hline x=0 & 0 & \text { minimum } & 5\end{array}$