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Compare the Right-Hand and Left-Hand Derivatives to Determine Whether or Not

Question 136

Multiple Choice

Compare the right-hand and left-hand derivatives to determine whether or not the function is differentiable at the point whose coordinates are given.
- Compare the right-hand and left-hand derivatives to determine whether or not the function is differentiable at the point whose coordinates are given. -   y = \frac { 1 } { x } \quad y = - 1    A)  Since  \lim _ { x \rightarrow 1 ^ { + } } f ^ { \prime } ( x )  = 0  while  \lim _ { x \rightarrow 1 ^ { - } } f ^ { \prime } ( x )  = 1 ,  f ( x )   is not differentiable at  x = - 1 . B)  Since  \lim _ { x \rightarrow 1 ^ { + } } f ^ { \prime } ( x )  = - 1  while  \lim _ { x \rightarrow 1 ^ { - } } f ^ { \prime } ( x )  = 0 , f ( x )   is not differentiable at  x = - 1 . C)  Since  \lim _ { x \rightarrow 1 ^ { + } } f ^ { \prime } ( x )  = 0  while  \lim _ { x \rightarrow 1 ^ { - } } f ^ { \prime } ( x )  = - 1 , f ( x )   is not differentiable at  x = - 1 . D)  Since  \lim _ { x \rightarrow 1 ^ { + } } f ^ { \prime } ( x )  = 0  while  \lim _ { x \rightarrow 1 ^ { - } } f ^ { \prime } ( x )  = 0 ,  f ( x )   is differentiable at  x = - 1 . y=1xy=1y = \frac { 1 } { x } \quad y = - 1


A) Since limx1+f(x) =0\lim _ { x \rightarrow 1 ^ { + } } f ^ { \prime } ( x ) = 0 while limx1f(x) =1\lim _ { x \rightarrow 1 ^ { - } } f ^ { \prime } ( x ) = 1 , f(x) f ( x ) is not differentiable at x=1x = - 1 .
B) Since limx1+f(x) =1\lim _ { x \rightarrow 1 ^ { + } } f ^ { \prime } ( x ) = - 1 while limx1f(x) =0,f(x) \lim _ { x \rightarrow 1 ^ { - } } f ^ { \prime } ( x ) = 0 , f ( x ) is not differentiable at x=1x = - 1 .
C) Since limx1+f(x) =0\lim _ { x \rightarrow 1 ^ { + } } f ^ { \prime } ( x ) = 0 while limx1f(x) =1,f(x) \lim _ { x \rightarrow 1 ^ { - } } f ^ { \prime } ( x ) = - 1 , f ( x ) is not differentiable at x=1x = - 1 .
D) Since limx1+f(x) =0\lim _ { x \rightarrow 1 ^ { + } } f ^ { \prime } ( x ) = 0 while limx1f(x) =0\lim _ { x \rightarrow 1 ^ { - } } f ^ { \prime } ( x ) = 0 , f(x) f ( x ) is differentiable at x=1x = - 1 .

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